511 karma · joined July 21, 2012
ben@ben-johnson.me
One thing that stands out as special to me, since it started out as an app for dance videos, so much of the cultural threads still revolve around that, and so it encourages an embodied way of presenting yourself. It makes text heavy sites like twitter and facebook feel... detached, cerebral, sterile in comparison. Whereas tiktok keeps a playful frivolity that that is so often lacking online. It seems to me a big step towards solving the big challenge with "online culture": considering the human.
Actually re-reading your post you probably know that already! Nevermind then. Maybe someone reading this will be enlightened
Just run a Linux hyper-v vm. That's what WSL2 is doing under the hood anyway. I run it this way and it's great. I have windows terminal auto ssh into it. Performance is great. And using the X server x410 on the windows side gui performance is fantastic (though no hardware acceleration) because instead of ssh tunneling x410 suports AF_VSOCK for the x socket, which hyper-v supports for performance as good as a domain socket on the same machine.
I work for one of these bespoke ERP companies, our niche is CNC machine shops (huge industy you don't hear much about). Our software was grown organically out of tools we made to manage our own CNC shop, spun out into its own company. That deep domain knowledge is what allows us to make a competitive product.
If this kind of stuff interests you we're hiring: https://www.proshoperp.com/company/careers/
[0]: https://home.sandiego.edu/~shulman/papers/rabbithole.pdf [1]: https://news.ycombinator.com/item?id=18411935
[0]: https://www.reddit.com/r/DrugNerds/comments/15m9sf/mdma_supp...
Interesting to note, the napkin creates a uniform gravitational field above and below it. Meaning that the force applied to an object is the same regardless of how far away it is from the napkin! That force is 2pi * G * m * rho where rho is the mass density of the napkin.
The drop off applies because the force of gravity is proportional to 1 / distance^2, so in this case the napkin would still have infinite mass, but it would not have infinite density, so if you took a surface integral of the gravitational force provided by each point in the napkin, over the whole napkin, it would converge on a finite value, as each point contributes less and less force as you get father away.