This person is trolling all of you. Look at this post he/she made nearly four years ago: https://news.ycombinator.com/item?id=7803526
8 karma · joined October 9, 2012
However, one thing this algorithm can do that Binet's formula can't is compute the N-th Fibonacci number modulo some constant M in O(log N) time. So you could very efficiently compute, say, the last 12 digits of F_123456789. A lot of programming contests (TopCoder, Google Code Jam, etc.) will ask for the answer modulo some constant to take advantage of this trick.
[1] http://en.wikipedia.org/wiki/Fibonacci_number#Closed-form_ex...