* Chiptunes (I recommend maktone and dubmood)
* Daft Punk, Ratatat
* Anything I know by heart -- I won't be distracted by the lyrics. This also works if you don't understand the lyrics
2,107 karma · joined May 1, 2010
ask me about analytics - luke@supernova.ai
* Chiptunes (I recommend maktone and dubmood)
* Daft Punk, Ratatat
* Anything I know by heart -- I won't be distracted by the lyrics. This also works if you don't understand the lyrics
Of course, a determined spammer will overcome these hurdles. But most spam bots don't bother.
Now I'm not saying these issues are present in Facebook Connect, but I don't have the time to find out and I don't want to gamble that everything will be dandy in the future, especially with a company so removed from ethics as Facebook.
When you name a new product using your old and renowned brand (like Facebook Connect using Facebook), both positive and negative karma is inherited from the old brand. This also may explain why some don't like FB Connect.
And, if you use another company's product (like with Quora and FB Connect), you risk inheriting the consequences of its negative karma as well.
Imagine the horror of graph theory for him (e.g. ∃x,y E(x,y), etc.)
"One of the myths of "Uberman sleep schedule" is that it makes it possible to enter REM sleep and skip non-REM sleep stages entirely. That myth is derived from another false claim that implies a non-essential role of deep sleep. I will ignore these claims as standing in total disagreement with laboratory findings and models of sleep. Instead, let us focus on a more plausible claim of the possibility of compressing sleep stages.".
I.e. "I will ignore one of my opponent's arguments and instead focus on another. Since I can rebuff the other argument, my original viewpoint is true". It's a logical fallacy.
He also tends to say "X is unnatural/abnormal" => "X is unhealthy".
I wish someone did serious research into the topic without prejudice.
You can do that via an agent. You can find one by googling 'Delaware Inc' or 'Delaware LLC' or by looking at the official list of registered agents at http://corp.delaware.gov/agents/agts.shtml. It usually costs around $200-$300 per annum for the basic service.
An interesting fact is that this is sufficient to express + and :
a + 0 = a a + (succ b) = succ (a + b)
a 1 = a a * (succ b) = a + a * b
One way to look at structures (like, say, natural numbers) is too look at what really defines them, as in, what is absolutely necessary and sufficient to define them? In this case, 0 and succ is.
Note that I'm not saying you're wrong, everyone is entitled to their own definition of beauty. Isn't that the beauty of it?
It contains 0, 1, +, , ^, which are sufficient to express all of elementary natural arithmetics (unless I'm mistaken) -- all natural numbers can be expressed by adding enough ones to a zero (0, 0+1, 0+1+1, ...), and if I recall correctly, + and aren't enough to state all the truths in natural arithmetics so ^ is needed.
There is a very interesting paper on this called "The saga of the High School Identities" by S. Burris (http://www.math.uwaterloo.ca/~snburris/htdocs/MYWORKS/PREPRI...)
Moreover, it contains three very attractive (if not the most attractive) mathematical constants we know. There is so much we don't know about their relationship. We have no idea if any of these numbers is transcendental or not: pi + e, pi − e, pi*e, pi/e, pi^pi, e^e, pi^e. We don't even know if half of them are even irrational or not (therefore, we don't know if pi is just another facet of e, or maybe an entirely different object!)
So to see all this (and more; one could say so much more) in one equation so terse is so surreal a feeling.
I referenced the fact that
e^x = 1 + x/1 + x^2/(2!) + x^3/(3!) + ...
Now, one of the many equivalent definitions of e is that it is the only real number for which this holds:
d/dt (e^t) = e^t
This means that e^t is a real function which is so smooth, that no matter how many times you differentiate it, you always get the same function (it turns out that it is the only such real function)
Now, we know that e^0 = 1 (since x^0 = 1, where x != 0). Therefore, in its Maclaurin series, the only term not depending on x should therefore be 1 (otherwise e^0 wouldn't be 1).
So know we know that e^x looks something like this:
e^x = 1 + (something)
Now we can ask ourselves which this question: since d/dx e^x = e^x, what must also be in the e^x series, if 1 belongs to it? Well, whatever differentiates to 1, so now we know that
e^x = 1 + x + (something)
(because d/dx (1 + x + something) = 1 + x + d/dx something)
Now we can again ask this question for our current form; what must we differentiate in order to obtain 1 + x? And thus we get
e^x = 1 + x + x^2/2 + something
This way, if we write the two (equivalent) series this way:
e^x = 1 + x + x^2/2 + d/dx e^x = 1 + x + x^2/2 + x^3/(2*3) +
And we can complete it with the infinite Maclaurin series.
Now this is less formal than it should be and it would probably make the formalists cringe, but I hope you get the idea. You can actually apply the same principle for sin x and cos x, except in their case, they're actually mutually derived from each other. I'll leave that as an exercise for the reader (oh how fun it is to say that after reading this phrase countless times)
e^x = 1 + x/1 + x^2/(2!) + x^3/(3!) + ...
If you substitute ix for x, you get:
e^{ix} = 1 + ix/1 + (ix)^2/(2!) + (ix)^3/(3!) + ... = = 1 + ix + (-x^2)/(2!) + (-i)x^3/(3!) + ...
You can also derive the Taylor series for sin x and cos x, which are:
sin x = x - x^3/(3!) + x^5/(5!) + ...
cos x = 1 - x^2/(3!) + x^4/(4!) + ...
Therefore you can see that e^{ix} = cos x + i(sin x). Of course, I haven't shown how to derive the Taylor series (http://en.wikipedia.org/wiki/Taylor_series) for these functions, but I have to stop somewhere.
I hope that I have shown you that this isn't just an arbitrary convention, in fact far from it. The formula is so beautiful also because of the many intricate relationships between all these elementary mathematical concepts, including complex analysis, trigonometric functions, series, etc.
It should also be noted that this is just one of the many (in fact, aleph zero many) different ways to prove this equivalence.
Edit: Some formatting corrections, sorry, new here.