Yes and another that uses a fixed ridiculous combination like 1 2 3 4 5 6 7 8 9. This is my favorite way for bringing the odds nearer to mind.
11 karma · joined January 22, 2014
Another example: compare the two algorithms, that are actually pure-mathematically equal:
def fc(x):
return sqrt(x+1) - sqrt(x)
def fd(x):
return 1/(sqrt(x+1) + sqrt(x))
xs = np.linspace(10\*14,10\*16,10000)
plt.figure(figsize=(8, 6), dpi=120)
plt.plot(xs,[fc(x) for x in xs])
plt.plot(xs,[fd(x) for x in xs])