Idiomatic underscore.js solution:

  for (var i = 1 ; i <= 100; i++) {
    console.log(
        _.chain(["Fizz", "Buzz"])
        .zip(_.map([3, 5], function(n) { return i%n;}))
        .where({"1": 0})
        .pluck(0)
        .value().join("")
    || i);
  }