The way that I've tried to explain/understand the Monty Hall problem is to expand it to 100 doors.

You're allowed to pick 1 door out of 100. Your chance of being correct is 1%. Then, the host gives you the option of swapping to the entire other set of 99 doors. Of course, your chance of hitting the car would be 99%, so you swap.

Opening 98 doors with goats behind them is expected, and so just because the host chooses to open 98 goats in a row doesn't mean that the chance of the last 2 doors (your final door out of the 99, and your original 1 door) both have an equal chance. Your set of 99 doors was opened in a specific order and that's what actually matters. The 99th door still has a 99% chance to contain the car, because your set had a 99% chance to contain the car. The order is everything!