if the stopwatch uses base 10, the last digit will be in the range [0, 9], making n >=10 irrelevant. in this range, 0 and 1 appear 3 times; 2 and 3 appear 2 times.
if the stopwatch uses hex, then 0-3 will appear equally often in this case
if the stopwatch uses hex, then 0-3 will appear equally often in this case
> if the stopwatch uses hex ...
I think we're safely in the red herring zone now. :)
EDIT: Yes, of course -- when confronted by a correct and reasoned reply, downvote it to discourage any such mistakes in the future.
Digits, not digit, please, and do try to limit the anti-intellectualism and adversarial posture.