if(n&1)
else
else
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
if (argc < 2) {
fprintf(stderr, "Usage: %s <string>\n", argv[0]);
return 1;
}
char *s = argv[1];
int i;
/* find the end of the string */
for (i = 0; s[i] != '\0'; ++i)
;
/* make sure the string wasn't empty */
if (i == 0) {
fprintf(stderr, "Error: empty string\n");
return 1;
}
/* last character is at s[i - 1] */
char d = s[i - 1];
if (d == '0')
printf("even\n");
if (d == '1')
printf("odd\n");
if (d == '2')
printf("even\n");
if (d == '3')
printf("odd\n");
if (d == '4')
printf("even\n");
if (d == '5')
printf("odd\n");
if (d == '6')
printf("even\n");
if (d == '7')
printf("odd\n");
if (d == '8')
printf("even\n");
if (d == '9')
printf("odd\n");
return 0;
}
gcc -std=c11 -Wall -Wextra -O2 -o check_digit check_digit.c./check_digit 999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
if (d & 1)
printf("odd\n");
else
printf("even\n") #define _(e) { e;};
#define r(e) _(return e)
#define I(b, e) _(if (b) r(e));
#define W(e) _(while (1) _(e));
int main(int c, char **v) {
_(I(c != 2, -1) _(c = 0) W(I(!v[1][c++], v[1][c - 2] & 1)))
} number="$1"
if [[ "$number" =~ "^(2|4|6|8|10|12|14|16|18|20)$" ]]; then
echo even
elif [[ "$number" =~ "^(1|3|5|7|9|11|13|15|17|19)$" ]]; then
echo odd
else
echo Nan
fi
A bit limited, but you can scale it up case "$1" in
*0|*2|*4|*6|*8) echo even;;
*) echo odd;;
esac
If $1 had a trailing non-digit, or was empty, that would indeed be an odd situation!