foo(bar()?)?
over something like if a, err := bar() {
return nil, err
}
if b, err := foo() {
return nil, err
}
But also even better is just let a = bar()?;
let b = foo()?; foo(bar()?)?
over something like if a, err := bar() {
return nil, err
}
if b, err := foo() {
return nil, err
}
But also even better is just let a = bar()?;
let b = foo()?;Edit: actually, it was someone else who said this: "Human brain has a funny way of learning how to turn off the noise and focus on what really matters.".
I have fixed (and frankly, caused) many bugs in golang code where people’s brains “turned off the noise” and filtered out the copypasta’d error handling, which overwrote the wrong variable name or didn’t actually bubble up the error or actually had subtly wrong logic in the conditional part which was obscured by the noise.
Frankly, learning to ignore that 80% of your code is redundant noise feels to me like a symptom of Stockholm syndrome more than anything else.
One symbol to replace three lines of identical boilerplate is no less explicit and dramatically clearer.
fn foo() -> Result<(),FooError>
bar()?
fn bar() -> Result<(),BarError>
If FooError can be created from BarError, the compiler will insert the conversion call and errors bubbles up nicely. nil, err
without the return and it would happily compile. It’s also tragically easy for actual logic bugs to be obscured by all the boilerplate.It’s not like three lines of error handling copypasta is some optimal amount. If golang required ten lines of boilerplate error handling, you’d still have just as many people arguing in favor of it because they “like it to be explicit” when it reality it’s verbose and the real underlying argument is that it’s what they’ve grown accustomed to. `?` is no less explicit, but it is less unnecessarily verbose.