Isn't the whole point of their design that they aren't producing neutrons? What's the point of picking an aneutronic reaction if they are going to be having D-D and D-T fusion going on anyway?
Unless they are planning to use an insanely high temperature (like 1B K or something)
[1] https://en.wikipedia.org/wiki/Nuclear_fusion#/media/File:Fus...
My reasoning is that, at plausible temperatures, D-D fusion is say 5x more frequent than D-He3 reactions, and then D-T fusion is ~1000x more reactive than D-He3.
So if 0.1% of the He3 fuses, then ~0.5% of the sample will become tritium, most of which will fuse.
Either I'm significantly overestimating the amount of reactants that are expected to fuse in each cycle, underestimating their target temperature, or they plan on have a very helium-rich mix of fuel.