A white dwarf's density is apparently around 1e9 kg/m³. Olympic swimming pools at 50m*25m*2m * 1e9kg/m³ would have a weight of 2.5e12 kg. As a sphere, the radius is (solving: volume_of_sphere = 4/3×π×radius³)

    $ qalc 50m*25m*2m = 4/3*pi*x^3
    (((50 * meter) * (25 * meter) * (2 * meter)) = ((4 / 3) * pi * (x^3))) =
    approx. (x = 8.4194515 m)

Gravitational acceleration (for a point mass) is: the gravitational constant, multiplied by the mass, divided by the radius squared, and we want the result in Earth gravities:

    $ qalc G * 2.5e12kg / 8.4194515² m² to gee
    (newtonian_constant * ((2.5 * (10^12)) * kilogram)) / ((8.4194515^2) * (meter^2)) =
    approx. 0.24 gee

You're only one order of magnitude off — if this is correct, which I am really not sure about!

Sources: https://en.wikipedia.org/wiki/White_dwarf · https://en.wikipedia.org/wiki/Olympic-size_swimming_pool · https://duckduckgo.com/?q=volume+of+a+sphere&ia=answer · https://www.wolframalpha.com/input?i=surface+gravity+calcula...

What I'm even less sure how to calculate is whether an 8-meter sphere can be that heavy. Uranium is ~2e4 kg/m³, but under its own gravity, things shrink until they reach black hole status (infinite smallness; perceived size coming from its event horizon). Basically I'd want to turn the above 1e9kg/m³ into an unknown, but what's the formula for mass given your specified radius and gravitational acceleration? TBD

I'm really curious if this was just a few words strung together and it happened to come out to within one order of magnitude by pure coincidence, or if (how) you calculated this!