It's *roughly* the gravitational acceleration at the surface of an Olympic-size swimming pool of electron-degenerate matter from a white dwarf star. Hope this helps!
(Note: the swimming pool has collapsed under its own weight and is now a sphere).
(Note: the swimming pool has collapsed under its own weight and is now a sphere).
$ qalc 50m*25m*2m = 4/3*pi*x^3
(((50 * meter) * (25 * meter) * (2 * meter)) = ((4 / 3) * pi * (x^3))) =
approx. (x = 8.4194515 m)
$ qalc G * 2.5e12kg / 8.4194515² m² to gee
(newtonian_constant * ((2.5 * (10^12)) * kilogram)) / ((8.4194515^2) * (meter^2)) =
approx. 0.24 gee
Sources: https://en.wikipedia.org/wiki/White_dwarf · https://en.wikipedia.org/wiki/Olympic-size_swimming_pool · https://duckduckgo.com/?q=volume+of+a+sphere&ia=answer · https://www.wolframalpha.com/input?i=surface+gravity+calcula...
What I'm even less sure how to calculate is whether an 8-meter sphere can be that heavy. Uranium is ~2e4 kg/m³, but under its own gravity, things shrink until they reach black hole status (infinite smallness; perceived size coming from its event horizon). Basically I'd want to turn the above 1e9kg/m³ into an unknown, but what's the formula for mass given your specified radius and gravitational acceleration? TBD
I'm really curious if this was just a few words strung together and it happened to come out to within one order of magnitude by pure coincidence, or if (how) you calculated this!
Oh shit you're right. Root cause: I saw "3 g" and wrote "3 m/s^2".
What calculation did you use though? Like some formula or is there a web utility for this, for example?
If so, that is surprisingly similar to what I ended up with when trying to validate it!