I think it claims the opposite, that P != NP:
> Since there is at least one algorithm (WESP) that is NP (verifiable in polynomial time) but not P (solvable in polynomial time), P cannot be the same set as NP.
> Since there is at least one algorithm (WESP) that is NP (verifiable in polynomial time) but not P (solvable in polynomial time), P cannot be the same set as NP.