How is it possible to both detect a photon and then allow it to travel to the human eye? Wouldn't detection require absorption of the photon?
How is it possible to both detect a photon and then allow it to travel to the human eye? Wouldn't detection require absorption of the photon?
If done correctly, the outgoing laser light and the two photons all travel in different directions and so can be separated and further directed using mirrors or optical fiber cables.
Because the process is non-deterministic, what we usually do is direct one of the photon beams towards a "heralding" [1] detector, while the other is directed towards the optical setup where we need a single photon [2]. If at a given moment a photon pair is produced, then the heralding detector will click; which tells us that is also a photon currently in our optical setup.
Finally, there is a ~p^2 probability that two photon-pairs will be produced at the same time by this process (and p^3 etc). To eliminate this possibility, in this experiment their heralding detector can detect how many photons landed on it any given moment. So if they see 2 or more photons in their heralding detector, then they discard this run, because now there are multiple photons heading towards the human eye.
[1] Herald as in the guy who announced that the King was approaching.
[2] In this case, towards the human eye.
+---------------------+
| Heralding detector |
| |
+---------------------+
/
/
+----------+ / Photon 1
| | /
Laser beam ------> | Crystal | ------------> Outgoing laser beam
| | \
+----------+ \ Photon 2
\
\
To human eyeLeonard Susskind explained it like this in one of his lectures (they are on YouTube, he's an excellent explainer):
From the moment the photon is emitted, to the moment it's detected, the photon exists in entanglement with all the intermediary things it "touched". Only at the final location it's "absorbed" (with a probability). At the intermediary locations the probability ended on the low side so it passed through.