If x is the interval [-1, 1], the typical implementation of IA will
evaluate x-x to [-2, 2] (instead of [0, 0], and
evaluate x*x [-1, 1] instead of [0, 1].
Therefore the intervals become too conservative to be useful.
evaluate x-x to [-2, 2] (instead of [0, 0], and
evaluate x*x [-1, 1] instead of [0, 1].
Therefore the intervals become too conservative to be useful.
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