The difference is between the information being offered, and determined independantly. I'll do this with the boy/girl problem, for simplicities sake.
If we ask a man if he has at least one boy, and he says yes, we can work out the chance the other child is a boy like so:
Assume all four possibilities are equally likely:
BB
BG
GB
GG
If we ask him if he has at least one boy, and he says yes, we effectively filter off GG, which brings the list down to: BB
BG
GB
Therefore, the chance of the other child being a boy is 1/3. Pretty straight forward.However! Because the father offered the information on his own, it effectively turns it into the author's other problem, where the older child is a boy, find out the gender of the younger child.
The trick is that he's equally likely to give information about either of his children, therefore there are eight possibilities:
He gives information about child A:
BB - B
BG - B
GB - G
GG - G
He gives information about child B: BB - B
BG - G
GB - B
GG - G
There are still 3 possibilities, but BB is twice as likely as the others, because if both children are a boy he's definitely going to reveal the gender of one of them as a boy; whereas if one is a girl and one is a boy, there's only a 50% chance he will. BB - 50%
GB - 25%
BG - 25%
So, the answer to this:You meet a man on the street and he says, “I have two children and one is a son born on a Tuesday.” What is the probability that the other child is also a son?
Is 1/2
The answer to this:
A man has two children, and one is a son born on a Tuesday. What is the probability that the other child is also a son?
Is 13/27
It's nitpicky, but I think the author should be very exact about this kind of thing, since he's trying to clear things up.