Since that number is about the average risk of an american to die (and not the risk per flight), using it to calculate the risk per flight is erroneous
I think?
Anyway, happy to be corrected.
so your probability of dying from one flight (all of the world considered - way lower for US afaics) looks to be 1 in 17 millions in 2019
[1] https://www.statista.com/statistics/263443/worldwide-air-tra... [2] https://www.statista.com/statistics/564717/airline-industry-...
If there's a very dangerous airplane ride that results in 10% of all flights ending in crash, if you take that plane 10 times, wouldn't you expect 1 crash on average?
Probability of dying on one flight: 1/10,000,000
Probability of surviving one flight: 1-1/10,000,000 = 9,999,999/10,000,000
Probability of surviving 100 flights: (9,999,999/10,000,000)^100
Probability of not surviving 100 flights: 1-(9,999,999/10,000,000)^100 ~ 1/100,000.
I don’t know if the initial assumption of 1/10,000,000 survival rate is accurate, but the math is correct.
And when you have a probability that’s very small, you can skip all that and approximate by multiplying the probability by the number of events: 1/10,000,000 * 100 = 1/100,000. That’s thanks to the binomial approximation.