4(9μ + 16φ + 6Ω - 200) + 3Ω - 1 + 2(2Δ - μ) + 9(9β - 5Δ - 3Ω ) = 0

10(4β - 4Δ + 3Ω ) - Δ + μ + β - 3 - 8Ω + 11(5μ - 2Ω + 4φ) = 0

9(2Ω - 4Δ + 6φ) - 15Ω - 3(Ω + 1 - Δ) + 5(7μ + 5β - 13) = 0

10(2Ω - 600 + 5φ + 6β) + 3(β - μ) + φ + μ - 4(6Δ - 8μ + 5Ω ) = 0

Reduce it enough, and Wolfram Alpha generates a visual representation of a plane. But this is also a puzzle - I think the key isn't getting an equation out of it, it is figuring out where they want us to apply said equation.