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Comment by cygaril | Hacker News Reader
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cygaril
·
I think you were right the first time.
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oefrha
·
Nah, 3 (0b11) and 5 (0b101) differ by 2^1 but differ by two binary digits. Or 7 (0b111) and 11 (0b1011). But as I said it’s a starting point.
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