I wonder if this technology will ever be viable for commercial flights in the future. What the safety procedures would look like at that speed.
The formula is (m*v^2)/2.
Plugging in the figures, we get 2.9 MJ, or the equivalent of a little more than half a kg of TNT. Not bad :D
Thanks for the correction, HN!
And the vehicle needs to work at completely different altitudes and velocities. This could be very challenging in terms of structures, landing gear, braking etc. Particularly if the mass of the vehicle is constrained. Many component will need to be lighter and have orders of magntitude better performance than a traditional airliner.