No, what you described is implementation-defined behavior.
It may be confusing, but here's the breakdown of different kinds of behavior in the C standard:
* Well-defined: there is a set of semantics that is defined by the C abstract machine that every implementation must (appear to) execute exactly. Example: the result of a[b].
* Implementation-defined: the compiler has a choice of what it may implement for semantics, and it must document the choice it makes. Example: the size (in bits and chars) of 'int', the signedness of 'char'.
* Unspecified: the compiler has a choice of what it may implement for semantics, but the compiler is not required to document the choice, nor is it required to make the same choice in all circumstances. Example: the order of evaluation of a + b.
* Undefined: the compiler is not required to maintain any observable semantics of a program that executes undefined behavior (key point: undefined behavior is a dynamic property related to an execution trace, not a static property of the source code). Example: dereferencing a null pointer.
§3.4.0: behavior: external appearance or action
§3.4.1: implementation-defined behavior: unspecified behavior where each implementation documents how the choice is made. EXAMPLE: An example of implementation-defined behavior is the propagation of the high-order bit when a signed integer is shifted right.
§3.4.2: locale-specific behavior: behavior that depends on local conventions of nationality, culture, and language that each implementation documents. EXAMPLE: An example of locale-specific behavior is whether the islower function returns true for characters other than the 26 lowercase Latin letters.
§3.4.3: undefined behavior: behavior, upon use of a nonportable or erroneous program construct or of erroneous data, for which this International Standard imposes no requirements. NOTE: Possible undefined behavior ranges from ignoring the situation completely with unpredictable results, to behaving during translation or program execution in a documented manner characteristic of the environment (with or without the issuance of a diagnostic message), to terminating a translation or execution (with the issuance of a diagnostic message). EXAMPLE: An example of undefined behavior is the behavior on integer overflow.
§3.4.4: unspecified behavior: use of an unspecified value, or other behavior where this International Standard provides two or more possibilities and imposes no further requirements on which is chosen in any instance. EXAMPLE: An example of unspecified behavior is the order in which the arguments to a function are evaluated.
[1]: WG14 working paper for the C11 standard: http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1570.pdf
If it were otherwise, you couldn't `memcpy()` structures around.
I'll check the unbelievably thick book that tries to specify C11 (I've printed it, it's over 2 pounds).
Why not just have the compiler zero the memory, and thereby remove the trap? Seems very sensible to me. Do you think it’s a bad idea, and if so, why?
As a type qualifier keyword:
{ int x, y; /* x and y are zero */ }
{ int noinit x, y; /* x is indeterminate, y is zero */ }
Or as a declaration specifier: { noinit x, y; /* both x, y indeterminately-valued */ }
Or a special constant for suppressing zero initialization: { int x, y = noinit; /* x zero, y indeterminate */ }
Similarly, unspecified order of evaluation could be supported by explicit request: decl (unspec_order) { /* comma-separated list of decl items */
a[i] = i++; /* UB */
}
a[i] = i++; /* well-defined */ static int x, y; /* x and y are zero */Oh no no no, I was picking on hermitdev's characterisation of the behaviour. Sure, what the compiler does with the padding bytes is unspecified. But it can still lead to undefined behaviour, if some unwary user ever reads them. A misinterpretation like that, and poof you get a security vulnerability. The C standard is insane.
Modern processors, with their out-of-order execution, complex caching algorithms, deep pipeliens and multi-threaded hardware often render this sense of control more illusory than factual, but the C culture remains wedded to the idea that the programmer is in control.
Accordingly, it's pretty provocative to suggest that a compiler or runtime would zero out memory without you specifically saying so. Any C programmer can overload malloc (doesn't zero memory) to calloc (which does). Whether it's a good or bad idea to do so is up to the programmer. The overall idea is don't do anything unless I say so.
No nukes get involved here - only core dumps.
So it's unspecified in terms of the standard, but specified by the implementation