> photons are gauge bosons and thus are automatically their own antiparticle
So is W^+, but it is charged, hence not its own antiparticle. W^- should in this case be considered the antiparticle.
So is W^+, but it is charged, hence not its own antiparticle. W^- should in this case be considered the antiparticle.
The W0 and B0 mix to give the photon and Z0
The W+, W− and Z0 gain mass and the photon is left massless