Well the term is not very precise if the way that you're using it and the way the article is using it are completely different. The article makes it clear that the term "pass-by-value" refers to the fact that the callers' references cannot be unseated by the function call; but it does not mean deep copies are made, like by copy constructor, hence that's why it applies to Java. Allow me to illustrate:
vector<int> numbers;
void f(vector<int> args);
Due to C++'s copying, args[0] has a different address than numbers[0], because a deep copy of the vector was made. As the article states, this is not what pass-by-value is referring to, otherwise it would be false that Java / Python / Ruby et al are pass-by-value. So I disagree that the terms are clear, but rather that there is confusion around these terms. As for wanting immutability, it's almost always better for C++ code to write functions not like f but instead like this:
void g(const vector<int>& args);
And apologies for the editorializing, but I do consider this a language design flaw, one inherited from the backwards compatibility for C, which already allowed struct's to be passed (non-pointer) as args and then copied to keep the caller untouchable. It makes C++ code more verbose and more error prone, and is quite difficult for new programmers to grasp.