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Comment by DannyBee | Hacker News Reader

Right, but now you have the opposite problem. Let's say that before the compiler could move x=2 after bar (let's assume bar does not touch x).

Now, in your world, it can't.

So before, you would have seen x=1 in the call to bar, and now when you use the debug library, you will see x=2.

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But it's not really material, because bar doesn't touch x (and if it did, this problem wouldn't exist to begin with).

In other words, it might be a bit strange and cause a slight detour in your quest to discover the cause of a bug, but it wouldn't actually change any behavior or cause any issues.

Your argument is essentially: The barriers you insert, even if they block optimization, will never block optimization in a way that changes behavior. This is demonstrably false, since you are, among other things, taking the address of a variable, which means escape analysis won't do things to it, etc.

You can argue "The behavior it changes doesn't matter". As i've shown, 1. it does in a threaded environment (like, you know, go) 2. It depends on whether your code is buggy or not.

IT's certainly true that it never, on it's own, causes bugs. But as i've shown, it can make bugs appear to come or go.

If you don't think that will ever happen, i don't know what to tell you, other than "It has happened in literally every compiler that has ever had barriers like this".

Without any evidence why Go should be different here, i don't see why go will be different here.

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