As a completely fabricated example, suppose the true proportion in a coin flip experiment is 40%. If my confidence interval is [.45, .65], what's the probability that .40 is in [.45, .65]? It's 1. The probability that a fixed, but unknown parameter will lie in any confidence interval will be either 0 (it isn't in the interval) or 1 (it is). The _proportion_ of times the interval contains the true parameter is the level of confidence (95%).
To your always-positive example, that procedure is not particularly weird. There's always a balancing act with CI's about length and confidence level (otherwise, I could choose all reals as my interval and get 100% confidence level). That your [0, inf) interval has 100% coverage means that you could probably shrink that interval so that it has finite upper bound without losing more than 5% confidence. Hard to say without a specific distribution in mind or mild assumptions, but an application of either Markov's or Chebyshev's Inequality would allow you to make really loose bounds with only relatively minor assumptions.