Graham's Number
en.wikipedia.org
en.wikipedia.org
In those days, you either gave your professors little self-addressed stamped postcards to tell you your grade, or went to their offices to ask them. I took the latter approach with Rothschild. "What grade were you expecting?", he replied. I confessed that I thought I would probably get an A. "You're getting an F", he said. "I'm giving everybody the opposite of what they expect."
He once made me pull out a 1$ bill from my pocket in his office and then asked me what the serial number was, he shot out a question like: "what's the probability that you have n consecutive numbers on the bill".
You could tell Math was legitimately fun for him, he treated open math problems like brain teasers and that fun rubbed off on the people around him as well.
http://quant.stackexchange.com/questions/4201/strategies-for...
A. Write a question suitable for this course. B. Answer it. You will be graded on both parts.
Some of my favorite parts (minor spoilers):
> Look closely at that drawing until you realize how not okay it is. Then let’s continue.
> Then Graham decides that for g2, he’ll just do the same thing as he did in g1, except instead of four arrows, there would be NO I CAN’T EVEN arrows.
They also had another video [2] with Ron Graham himself :)
[1]: https://www.youtube.com/watch?v=XTeJ64KD5cg [2]: https://www.youtube.com/watch?v=GuigptwlVHo
The method used by the winning entry is extremely interesting: return the outputs of all possible programs up to a certain size which terminate according to the calculus of constructions. It's quite crazy to have done this in 512 chars.
Note that the Graham number can be written as G=f[64](4), where [.] means the number of iterations of f and f(4)=3\up\up\up\up3 (as in the article). Now you can define a function g(n) as g(n):=f[n](4), so G=g(64). g is computable since we just described an algorithm to calculates its values. So the busy beaver grows even faster (asymptotically) than g.
Sheesh.