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Comment by jarcane | Hacker News Reader

  map (\x -> chr (x + 32)) [45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1]

View on HN

    #include <string>
    #include <iostream>
    #include <algorithm>
    using namespace std;

    int main() {
        string s {33,78,68,0,65,0,40,65,80,80,89,0,46,69,87,0,57,69,65,82,0,79,70,0,
                  70,85,78,67,84,73,79,78,65,76,0,67,79,68,69,0,84,79,0,89,79,85,0,
                  84,79,79,12,0,51,73,82,1};
        transform (begin(s), end(s), begin(s), [](char c){ return c + 32; });
        cout << s << endl;
    }

Last one, in old-fashioned style:

  5 FORX=1TO16:READN:N=N+32:?CHR$(N);:NEXTX:DATA45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1

Coffee:

[45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1].map((x) -> String.fromCharCode x+32).join('')

What language is this?

Haskell. Here's another way to do it in the same language, using function composition and point-free style.

map (chr . (+32)) [45, 69, 82, 82, 89, 0, 35, 72, 89, 73, 83, 84, 77, 65, 83, 1]

Merry Xmas. I thought I'd try Haskell for the same time for Xmas and found I have to download it and import Data.Char first in case anyone else is trying!

Or in Perl:

  map{chr$_+32}(45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1)

shorter using pack:

  # shorts
  pack("s*",25933,29298,8313,26691,26994,29811,24941,8563)
  # longs
  pack("l*",1920099661,1749229689,1953720690,561209709)
  # 64-bit
  pack("q*",7512884309367350605,2410377348306397554)
  # hex
  pack("h*",d45627279702348627963747d6163712)

explain :)

Javascript

  [45, 69, 82, 82, 89, 0, 35, 72, 82, 73, 83, 84, 77, 65, 83, 1].map(function(x){ return String.fromCharCode(x +32)}).join('')

Copy-paste in your browser console -

    // Merry Christmas
    console.log(
      [45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1]
      .map(function(i) { return i + 32; })
      .map(function(i) { return String.fromCharCode(i); })
      .join("")
    );

I'm to lazy to do the math (substract and look for ascii code), but it should be "Merry Christmas". clue: look where "r" is i the string.

Python equivalent for convenience:

  map(lambda x: chr (x + 32), [45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1])

Just paste it into a python terminal and run it :)

Python 2/3 compatiblity:

    "".join(map(lambda x: chr (x + 32), [45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1]))

Or as a list comprehension if that's your thing:

    "".join([chr(x + 32) for x in [45,69,82,82,89,0,35,72,82,73,83,84,77,65,83,1]])

  ; Racket version
  (apply string (map (λ (x) (integer->char (+ x 32))) '(45 69 82 82 89 0 35 72 82 73 83 84 77 65 83 1)))

Scala

  List(45,69,82,82,89,0,35,72,89,73,83,84,77,65,83,1) map (_ + 32 toChar) mkString

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