Gray Code
datagenetics.com
datagenetics.com
Imagine a set of deeply nested if-then-else conditions that are dependent upon a fixed set of boolean flags - this is pretty common in a state machine. Reducing those conditions to a formula that calculates a boolean value is often far less taxing on a small uC.
So I brought out one of my Electrical Engineering books (The Art of Electronics by Horowitz and Hill), let them each read the section on Karnaugh Maps [1] and then ran through some examples using their decision networks. Watching those light bulbs come on was one of the favorite events in my career.
The biggest effect that Gray code had on my life was when it helped me pass an entrance exam to a math camp when I was pretty young (younger than most other students), because one of the questions on the entrance exam was "can you prove that there is or isn't a Hamiltonian circuit on any n-dimensional hypercube?".
The Hamiltonian path is a path that visits every node once, and a Hamiltonian circuit does this and also returns to the starting point.
https://en.wikipedia.org/wiki/Hamiltonian_path
Well, I knew about the binary Gray code from Martin Gardner (in his book Knotted Doughnuts and Other Mathematical Entertainments), and I realized that if you think of an n-bit number as a coordinate in n-dimensional space (like 10101110 is the coordinate (1, 0, 1, 0, 1, 1, 1, 0)), then the n-bit binary Gray code is already a description of a Hamiltonian cycle on the unit n-dimensional hypercube.
It tells you how to trace the path, because it tells you which vertices to go to in which order. Every transition from one number to the next is an edge of the cube because it involves changing exactly one bit (so, exactly one dimension), which is exactly what defines the edge of a cube (it's a movement in exactly one dimension). You visit every vertex because the Gray code includes every number, and as this linked article says, the default Gray code is cyclic and comes back to the original starting point at the end.
We know that there's a Gray code for any number of bits because there is a recursive reflective procedure for constructing them to any length (as described in this article): take the (n-1)-bit Gray code, write it forwards prefixed with 0 and then backwards prefixed with 1, and you have an n-bit Gray code. This also has a nice geometric interpretation, which is that given a Hamiltonian circuit on an (n-1)-dimensional hypercube, you can do it on the "lower" hypercube, go "up", do it backwards, and then come "down", and now you've created a Hamiltonian circuit on the larger n-dimensional hypercube.
This answer let me pass the test and get into the math camp, but I found it pretty difficult when I actually went, I think because I didn't exactly come up with this answer "on my own": Martin Gardner did a ton of the work for me in teaching me about Gray codes, and I had already been thinking about the isomorphism between binary numbers and hypercubes before for some reason.
Supposing your keyboard key input was latched by a flop and you pressed the key at the exact right moment you could violate the timings of the flop and have it end up in a metastable state.
That's why you usually put a bunch of delay flops when sampling such a signal in the hope that you'll manage to have a stable signal down the line, however that doesn't remove the problem altogether, it just makes the probability of the problem happening very low.
So we've got very, very good at the engineering analysis to make sure that even though it's actually analog we can have a meaningful conversation about things and pretend it's not.
Pressing a key on the keyboard would never do that because there's a little microprocessor built in that actually handles getting keypresses and transmitting them to the real computer. Could you crash that computer by pressing a key at exactly the right time? No. Because they've designed it so that even in the metastable state it handles things correctly. A key defaults to off. If there is enough evidence over a sample period that a key was pressed then report on. If there's not enough evidence, it's off. Switch debouncing is a well established and practiced discipline. http://www.ganssle.com/debouncing.htm
The debouncing examples in the article you linked to don't seem to eliminate the risk in a theoretical sense. The RC circuit is taking an analog function of an analog function to apply some smoothing and significantly decrease the effects of transients on the observed voltage at the ADC, increasing the proportion of the time it will spend in a well-defined range if driven by a noisy switch. There must still be some set of analog inputs that would keep the voltage in an ambiguous range, though. The SR latch can itself experience metastability. (And the software solution should be right out, because it starts from the assumption that each individual digital measurement of the switch state has produced a well-defined binary value that can be safely used as input to expressions and functions at the software level.)
Wikipedia says that chaining latches together merely (dramatically) reduces the probability of this behavior, rather than actually eliminating it, because each latch could in principle (though with ever-decreasing probability) introduce and maintain metastability in the latch following it.
https://en.wikipedia.org/wiki/Flip-flop_%28electronics%29#Se...
Wikipedia cites to this article
http://ibm-1401.info/AnomalousSynchronizer_ChaneyMolnar_IEEE...
which seems to say that it was understood in the 1960s that every interface between digital circuits with no common clock (as well as every interface from an analog to a digital circuit) presented a theoretically "fundamentally inescapable" risk of introducing metastability which could propagate into the digital system, and that this was thought to be a source of some practical errors in computing systems in the early 1970s.
You're right that any long chain of latches could end up metastable and screwed up. But this technique doesn't use latches, it uses multiple reads on an analog input which is interpreted digitally (but not an ADC) to preclude the possibility of any kind of undesired behavior.
The point was more that it was a single bit, not a 10 bit ADC that's used to make determinations about switches. From a theoretical perspective the idea of a 1 bit ADC makes sense. From an engineering perspective, it doesn't. Since I'm an engineer that's why I said what I did.
[0]: http://research.microsoft.com/en-us/um/people/lamport/pubs/b...
I'm trying to improve my intuition for why the physical exmaples in it are right. I found the examples of inevitable crashes and collisions disconcerting.
The author comments: It's possible to generate Gray codes without this restriction (though to be honest, I can't understand the value of this, as the step-change on the warp around would experience the exact problem we are trying to solve!)
Linear encoders seems to me a perfect application.
0 → 000 | 000
1 → 001 | 001
2 → 002 | 002
10 → 012 | 012
11 → 010 | 011
12 → 011 | 010
20 → 021 | 020
21 → 022 | 021
22 → 020 | 022
100 → 120 | 122
101 → 121 | 121
102 → 122 | 120
110 → 102 | 110
111 → 100 | 111
112 → 101 | 112
120 → 111 | 102
121 → 112 | 101
122 → 110 | 100
200 → 210 | 200
201 → 211 | 201
202 → 212 | 202
210 → 222 | 212
211 → 220 | 211
212 → 221 | 210
220 → 201 | 220
221 → 202 | 221
222 → 200 | 222 ABC -> A'B'C'
000 -> 100 -> 110 -> 111 -> 011 -> 001 -> 000 -> ...
This sequence requires minimal hardware to program A' = not(C) B' = A C' = B
Also easy to decode the states for control signals 000 = not(A) & not(C)
100 = A & not(B)
110 = B & not(C)
etc.
I remember this especially because I made a bug. I forgot false state prevention. If the circuit starts randomly at power up, it may enter this sequence 010 -> 101 -> 010 -> 101 -> 010 -> 101 -> ...
and it did at one test.http://www.datagenetics.com/blog.html
Once you start reading, you'll spend the rest of the day!