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I don't know the actual answer, but it may be that the display actually expects 32bpp, in which case it would be over the limit by a considerable amount.

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The above calculation was for 32bpp:

3 colors * 1 byte * (8 bits/byte) = 32 bits

I am sorry,but no it wasn't. 3*8 is 24 not 32. But in any case I don't think the display requires 32 bits, alpha is not necessary.

Thanks for the clarification. fwiw, I knew that alpha wasn't necessary, but vaguely remembered that DisplayPort might support displays that expected the entire 32 bit word to be sent. Looking at the specs, I don't see that. But it does show that DisplayPort supports 16 bits per component, or 48bpp.

FYI, Wikipedia's section on DisplayPort lists the resolution of 5120x2880 x 24bpp @ 60Hz as requiring 22.18 Gb/sec of bandwidth, see http://en.wikipedia.org/wiki/DisplayPort#Specifications

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