Could You See the Curvature of the Earth in This Airport?
wired.com
wired.com
http://en.wikipedia.org/wiki/Bedford_Level_experiment
TL;DR - use a theodolite with measurement poles at each end and in the middle. No iphones, laser pens or bowling balls needed. Sometimes it comes down to having the right tools for the job.
I was going to suggest something similar... just put the bowling ball at one end and if you can see the whole thing at floor level at the other end, it's straight, else it's curved.
Did the author of the article not bother to investigate the actual answer?
> How (if at all) do architects of large buildings deal with the Earth's curvature?
http://www.reddit.com/r/askscience/comments/29jrhq/how_if_at...
I think it will be very difficult to align a local to the local tangent of the earth's surface. Over a distance of 700m, the earth's surface deviates by about 4cm. This means we would have to align our laser to within 50 microradians in order to accurately measure the deviation of the earth's surface.
Further more, his two beam system is setup using two lasers spaced about 4m apart requires even greater accuracy. Let's imagine system 1 is aligned to the local tangent at one end of the terminal (x = 0m), system 2 is aligned to the local tangent 4 m away at x = 4m, and heights of the two beams are measured at the opposite end of the terminal (x = 700 m). The height difference between these two beams will be about 1 micron. If we assume that the beams are large enough that there is no spread in beam size, then each beam is about 3 cm in diameter. This means we need to measure the beam height to better 0.003% accuracy relative to the beam size. I think this will be a very difficult measurement.
I think there is a way you could very accurately measure the relative angle between two beams in a larger interferometer and two lasers, but I'll have to think about how it would look...
Regardless, it's always fun to think about this small corrections to our expectations. To be honest, I was a little surprised to think about it, 4cm of deviation over 700m is actually a bit larger than I expected.
That isn't to impugn the question, or the method, but that I'm less interested in whether the architects adjusted each each to be 4cm higher than they would need to be or not. Even if the airport were built over the course of 5 meters, in which the curvature would be (effectively) undetectable, the airport itself, being man-made, may exhibit irregularities caused by human error, shifting ground, variable bedrock, etc.
Regardless, the article was fantastically fun to read, as was your post.
In practice, it may be possible to somewhat reliably measure a difference in deceleration rolling the ball towards an end of the hall vs towards its center.
And of course, if one also has a scale, the weight of the ball can be used to see whether the floor is level.
Can you elaborate on this? Why would the weight be different if non-level? Unless you're meaning that the center-of-mass of the ball would be ~2 centimeters further from the center-of-mass of the Earth and 1/r^2 means a decrease?
A bowling ball rolled on a very long straight hall would (assuming nearly negligible resistance etc) actually accelerate toward the center, then slow down, reverse, and oscillate until it stopped in the middle (the lowest gravitational position) because relative to the curvature of the Earth a straight line is higher at the ends than at the center.
A bowling ball rolled on a very long level hall would keep going (until resistance or confused staff stopped it) because there would be no gravitational change.
It would only be at the center of the hall if that's where the floor were tangent with the Earth's circumference.
The author is confused. That statement would only be true on the Equator. In the northern hemisphere, the ball will always deflect to the right. If I put a pencil on a globe, I can intuitively understand why, sometimes for up to five minutes!
A couple of lasers, a couple of levels, 3-4 rulers, and coordinating measurements would do it.
Here's the original: http://arachnoid.com/carnival/index.html#Vertical
In the linked article, we also find this graphic used to make another point -- horizon distance: http://datagenetics.com/blog/june32012/globe.png
Here's the original, from my Web site: http://arachnoid.com/carnival/resources/horizon_distance.png
Look familiar?
- Guinness Book of World Records (1973) made it with the Verrazano-Narrows Bridge - http://books.google.com/books?ei=93b7U_XoBuT5yQPkqYGIBQ&hl=s...
- So did Henry Petroski in Engineers of Dreams: Great Bridge Builders and the Spanning of America: http://books.google.com/books?id=1J9qUcgoUvkC&pg=PT460&dq=cu...
- and Popular Science in December 1995 http://books.google.com/books?id=7n5BWbJWMXMC&pg=PA102&dq=%2...
It's not unique to the V-N Bridge. Here's a generic version in:
- a NASA report from 1978, Skylab EREP Investigations Summary, says "For example, the support towers on each side of a long suspension bridge are several centimeters further apart at the top than at the bottom because of the curvature of the Earth" http://books.google.com/books?id=MEYgAAAAIAAJ&q=%22bottom+be...
and two links for the same observation for the Humber Estuary Bridge in:
- The Guinness Book of Records (1993) - http://books.google.com/books?id=RsNPAAAAYAAJ&q=humber+estua...
- Transport, Volumes 1-2 - http://books.google.com/books?ei=sX77U-DMN8bmyQOUr4KgBQ&id=X...
That said, for Golden Gate-specific comments, see:
- Ghost Hunter's Guide to the San Francisco Bay Area (2005) ("The engineering is so perfect that the towers are actually five inches further apart at the top than the base to account for the curvature of the Earth.") http://books.google.com/books?id=oD52WFx2mykC&pg=PA71&dq=gol...
- Practical Digital Wireless Signals (2010) ("As an example, for the Golden Gate Bridge at San Francisco the tops of the towers are further apart than the tower bases by about 9 cm due to the curvature of the Earth") - http://books.google.se/books?id=itG9Zwf7eHAC&pg=PA261&dq=%22... .
Therefore, do you really believe that you are the originator of that fact, and due special attribution?
The basic idea is pretty obvious. People have been computing "astounding facts" attributable to the Earth's curvature for thousands of years. Golden Gate Bridge is a pretty obvious choice for computing the tangible spread of two apparently parallel towers: WTC towers were too close for a dramatic spread, and other than GGB there isn't any other pair of towers so universally known (at least to an American audience) which are identical and far enough apart for a spreading of inches. If I think about it long enough, I'll probably recall seeing the same computation & example in trigonometry class decades ago.
Just because you thought of it doesn't mean you're first - by a long shot.
Oh, and your sketch is wrong. The two lines labeled "R" aren't the same length.
lutusp's diagram is the arachnoid one. His labels are correct, it's the datagenetics one that has apparently incorrect labeling. The dashed red line is not R in length, but R + h, which is not clearly indicated though the apparent intent. The dashed line should stop at the circle and change color or something to indicate a second line segment.
That said, you're correct. Ignoring the person another similar diagram is here:
Next you are going to claim he stole your idea of a time machine. (Oh and your idea about calculus, and the English language).