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Comment by yummyfajitas | Hacker News Reader

I don't disagree with the main point, but Python already has quite a bit of this. A more pythonic version of the first example:

    @retry(DOWNLOAD_TRIES)
    def download(url):
        ...

    images = [download(u) for u in urls]

To check if a sequence x is ascending, you can use standard library functions:

    all( t[1] > t[0] for t in zip(x[0:-1], x[1:]) )

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Just

    zip(seq, seq[1:])

Won't work with iterator though.

itertools.islice would work.

No it won't, unless you `tee` an iterator first.

FYI, the official documentation of itertools has its very own pairwise example:

    def pairwise(iterable):
      "s -> (s0,s1), (s1,s2), (s2, s3), ..."
      a, b = tee(iterable)
      next(b, None)
      return izip(a, b)

https://docs.python.org/2/library/itertools.html#itertools.i...

for the record: the official itertools docs have a lot more examples than this one and they're all really worth knowing about if not studying.

Indeed:

    all(a < b for a,b in zip(seq,seq[1:]))

(Although one might want <= if checking to see if the sequence is sorted, rather than strictly ascending (that is, it can contain matching/repeated elements)).

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