Ok, I hope somebody has a really good logical explanation of this, or maybe even some other awesome examples?
which is a geometric sequence with common ratio 2/10000 and first term 1/10000
So it has an infinite sum of (1/10000)/(9998/10000) = 1/9998
Same for powers of 3: 1/9997
Actually 1/8 = 0.125 is an example of this; it just breaks down very early because 4+0.8+0.16+0.032+0.0064+... = 5
1/9998 = 1/(10000-2) = 1/(10000)*1/(1-2/(10000)
Since 2/10000 is very small, it is well approximated by the taylor expansion for 1/(1-x), which is simply
Sum(x^n)
Since x is 2/10000, we get powers of two, which keep getting shifted to the right. Like a bit pattern, they don't overlap when added, so we get the sequence above.
S = 0.00010002000400080016...
S = 0.0001 + 0.0000 0002 + 0.0000 0000 0004 + 0.0000 0000 0000 0008 + ...
S = 2^0 / 10000^0 + 2^1 / 10000^1 + 2^2 / 10000^2 + 2^3 / 10000^3 + ...
S = sum to infinity of (2/10000)^i
You might have noticed this is a geometric series with ratio 2/10000 = 0.0002. S = 0.0001 / (1 - 0.0002) = 0.0001 / 0.9998 = 1/9998so,
1/(1 - .0002) = 1 + .0002 + .0002^2 + ...
and
1/9998 = .0001/(1 - .0002).