I can see a potential argument that doing type checking via macros costs more than precompilation in efficiency terms, but on the other hand, that's not necessarily so. How does TypeScript do type checking for non-constant values? That is, if I define function foo(bar: string) in a TypeScript library, then compile it, load the library in a Javascript interpreter, and call foo(Integer.parseInt("42")), what happens? I'm guessing that either foo() misbehaves, or that foo() throws an exception.
In the former case, there is no benefit to TypeScript because your type annotations are evanescent and misleading -- you can't rely on them, so you either have to write fences around input values just like you would without them, or risk your code misbehaving because it's written to rely on unreliable type annotations.
In the latter case, TypeScript is adding those fences automatically, so that a function which expects an integer argument can check whether it actually got one and fail if it didn't. That's basically what a macro system implementing type checking would do, too, and it seems to me that in both cases optimization would be merely an implementation detail.