Problem "Where2"

Fails: SELECT facid, name, membercost, monthlymaintenance FROM cd.facilities WHERE membercost > 0 AND (membercost / monthlymaintenance) < (1/50);

Succeeds: SELECT facid, name, membercost, monthlymaintenance, (membercost / monthlymaintenance) as a FROM cd.facilities WHERE membercost > 0 AND (membercost / monthlymaintenance) < (0.02);