The actual paper ( http://libgen.org/scimag5/10.1002/anie.201302577.pdf ) says they manage an efficiency of 25 mWhL^-1 (90 joules per litre)
Where did you get that 0.7A number?
Where did you get that 0.7A number?
To make this technology energetically favourable to boiling, it must not exceed ~700μA in current, and it has to be far less than that to be worth its complexity.
Solving for current, Ohm's law is I = V/R. You only deliver .7 amps of current into a 4.285 ohm load.
If you connect a 3 volt battery to a 1,000 ohm resistor, then only 0.003 amps of current will flow, which is 9 milliwatts.
Connect a 3 volt battery to a .01 ohm load (a dead short, almost) and 300 amps of current will flow, (900 watts!) very briefly, until the battery voltage sags under load.
1: Or any voltage source in general, barring some trickery that you can't do with a simple electrochemical battery.
Can you please define the Current Push Theory?
http://en.wikipedia.org/wiki/Hydraulic_analogy
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/watcir.h...
E.g., if you have a resistive load and an inductive power source, the power source will keep upping its voltage until the load accepts the current that's being shoved down its throat.
Except it won't, of course, because all real batteries have internal resistance. (How much depends on the battery chemistry and size.) Probably the 700mA rating for the AA battery is into a dead short.