Talk about going overboard... furthermore this in combination with "Don't use words or "clever" variations on words" make it all but likely that you're going to forget your own password and write it down.
Talk about going overboard... furthermore this in combination with "Don't use words or "clever" variations on words" make it all but likely that you're going to forget your own password and write it down.
Instead of "E=E<4oc^(z&kj6Snm9uy" do something like "The Brown cow jumps over the m00n!".
Set the password manager to make you enter the password if you haven't used it for 30 seconds (for a few days so you remember your password).
You're using a password manager with a good password that is easy to remember but the you do use the password manager to generate hard to remember passwords like the one above.
Estimates of the entropy of English text place it below 1.5 bits per character. "The brown cow jumps over the moon." would, generously, have about 34 * 1.5 = 51 bits of entropy, plus a few more for the simplistic substitutions - say 70 bits total? This is assuming the sentence was, in fact, chosen uniformly across English sentences, which is obviously not going to be the case (this one being a modification of a line from a nursery rhyme), so in actuality it'll be even worse.
A fully random password of length 20, from characters on a typical keyboard (say 94, it seems to be on mine) would have 20 * lg(94) > 20 * 6.5 = 130 bits. But impossible to remember and a pain to type correctly.
Picking from my /usr/share/dict/words with no restrictions (99171 entries), it would take 70 / lg(99171) = 5 words to be stronger than the sentence and 130 / lg(99171) = 8 words to be stronger than the gibberish, with no substitutions or tweaks, however not all of those passwords could be typed on my keyboard.
Restricting /usr/share/dict/words to those which match (with LANG=C) '^[a-zA-Z]\{1,10\}$' yields 61078 words at about 7.3 bits of entropy per word, so you would get security comparable to the above with 5 (again - aliasing) and 9 words respectively.
Some nine-word passwords generated this way:
embryo distressed Ramadan chocks broaching official outstript explicit formulas
tokens bruskly realizing rubric earmarks aphorism sweeps hallelujah Bardeen
respects jocularity crummier leave spinsters Rodriquez hatch assurance torture
patinas Elba dairymaids blabbing kissing handyman Ind tobogganed directed
mossy Flora concepts medalist kidding heinously deafened evaluation nodes
Steinmetz lizard Janette scatted cunning geckos belched demurring grandest
faints nicest unleashes navel Monroe frostbites Pl loon careening
overtake tasselled quahog utters Upjohn incloses punchy Jericho reveille
sicked sinning premiere Satanism loiters accrual Caspar infatuate renewable
dinning hereabouts Lithuanian formalism voiceless demoted bundle teed fluent
The above were generated with
LANG=C grep "^[a-zA-Z]\{1,10\}$" /usr/share/dict/words | rl --reselect -c 10 | xargsThis is, obviously, reliant on an assumption that rl produces cryptographic level randomness, which is probably not the case but should certainly be near enough the case for examples (and in any case will be much, much closer to true than any method involving humans - we are very poor sources of cryptographic entropy).
I chose the passphrase "The Brown cow jumps over the m00n!" as an example not "The brown cow jumps over the moon." which is a significantly worse passphrase, especially considering every word is available in a dictionary.
The OP had trouble memorizing more than 16 characters for a passphrase so I suggested something easier yet still solid yet you seemed to think I suggested just a plain english sentence of words.
Anything you can generate without much more unpredictability from a plain English sentence is not a significantly better passphrase than a plain English sentence. Better? Yes. And I credited you for that.
Writing down your password is usually less risky than picking a weak password.
As always, assess the risks.