Infinite loop in C

Huh? Overflow in C doesn't cause a run-time error. Overflow of a signed integer is technically undefined but whatever the result is, it should just keep running.

There are so many things wrong with that code its not even funny...

First off counter is of type static int. not unsigned int like the article says. Secondly j is decremented, j isn't even defined.

They are however right that it most likely will crash due to an overflow problem. Though this is not necessarily true.