Why is the moon’s gravity so uneven?
web.mit.edu
web.mit.edu
Negative gravity? Do tell....
Or just refer to it as gauge gravity, which is what they've described (where zero is a reference to a nonzero absolute value).
http://www.bbc.co.uk/news/science-environment-22736709
"The space rock, which is called 1998 QE2, is so large that it is orbited by its own moon."
The rock is 1.7 miles across, and is orbited by another 600 metre rock. I find it bizarre that a rock only 1.7 miles wide has enough gravity to be able to have its own "moon".
* mostly water or ice: 1 g/cm^3
* mostly rock: 5 g/cm^3
* mostly iron or metals 8 g/cm^3
So density range of the usual solid material of asteroids is only ~10. This asteroid has a very low gravity. So maybe jumping from it can put you in orbit.
The easy way to understand what is imagining that you can turn off the gravity force between the asteroid and its moon. Now you have two independent asteroids that are orbiting around the sun. Both have almost the same position and velocity, so both have a very similar orbit. They will travel together for a long time, but the differences in the orbit will began to accumulate and they will start to slowly come apart.
Now turn on the gravity force between them. It's a small correction to the independent orbits but they are not separating very fast so a small force can keep them together. If you stand up in the bigger asteroid then the bigger asteroid will look like a moon.
(A better method to calculate the apparent orbit of the moon is to use a reference system that is fixed to the center of the asteroid. It's accelerating, so most of the gravity force of the sun cancels, but there are some tidal and centrifugal effects.)
At least to an observer sitting in a fixed point in outer space.
Edit: better explanation: http://www.badastronomy.com/bad/misc/moon_spin.html
The more you know...
Also, a rotating object does not need to produce or receive any force. The conservation of angular momentum says that unless a force acts on a system, it will continue to rotate at whatever angular velocity it is currently rotating at. This is because the system itself is not accelerating. If you look at a particlar subsection of the system (say at an end), then that subsection is accelerating due to a centrifugal force, but that force is contained within the system.
Even on the surface of the earth you can tell you are rotating, even inside a completely closed room. For example with a http://en.wikipedia.org/wiki/Foucault_pendulum
There are probably some impacts that have caused this on earth, but the difference in gravity is probably so small, that it doesn't effect orbits. (We could probably measure it though).