I may be totally mistaken, but doesn't the result depend on X and Y unit (or alternatively on the standard dev of the gaussian) ?
So in a certain sense, the strength of smoothed analysis is that by applying a small amount of noise to a problem (which you can sometimes argue is simply the process of solving it with fixed precision etc), you can destroy any fragile counterexamples to a good execution speed.
Theres a bit more going on, but thats the basic idea