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Comment by phoobahr | Hacker News Reader

sooo... Counter(re.findall(r"[^a-zA-Z]([a-zA-Z]+)[^a-zA-Z]",requests.get("http://blog.getbootstrap.com/2013/02/07/bootstrap-2-3-releas...).content.lower()))

I see one occurrence of 'shit'. I'm not sure how I feel about your pansy ass semi-outrage of someone else's release page language.

Oh, wait. I feel nothing, approximately what this entire conversation thread is worth.

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Ctrl + F shows two. Time to update your regex-fu, or use simpler tools.

re.findall() returns all non-overlapping matches. We need to use a positive lookahead on the third part of the pattern to stop it from consuming the non-character:

  re.findall(r"[^a-zA-Z]([a-zA-Z]+)(?=[^a-zA-Z])", ..)

If my comment seemed like a semi-outrage then you sir/madam are a very sensitive person.

Love the use of Counter & requests, but you get 76 li elements with your regex - one of which contains another occurance.

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