Negative temperatures are not colder than absolute zero
empiricalzeal.com
empiricalzeal.com
Physicists decided to define the temperature of a system not simply by the amount of energy in the system, rather to define it as the ratio of the energy in the system to the total entropy of that system. In so doing, they created a situation where systems that go to a lower entropy state when energy is added, are described as having a negative temperature.
(Of course, it's slightly more confusing since it's actually the inverse of the temperature that's defined as dS/dE, which is the rate at which the entropy increases as the energy increases, a much more understandable definition. And as the physics professor who taught this to a room of students from various departments said of the transition from
1/T = dS/dE
to T = dE/dS
"The mathematicians in the crowd will be in an uproar now. But we can do stuff like that in physics")T = ∂E/∂S is implied by the fundamental relation of (phenomenological) thermodynamics, whereas 1/T = ∂S/∂E gets derived from a microscopic theory via statistical mechanics.
Thing is, when you understand why it happens, it seems perfectly rational and expected. It's all about information.
Systems with positive temperature increase in entropy as
one adds energy to the system. Systems with negative
temperature decrease in entropy as one adds energy to the
system.
http://en.wikipedia.org/wiki/Negative_temperatureA system's entropy in statisical mechanics is k log W, where k is Boltzmann's constant and W is the number of microstates. The microstate is a configuration of, say, electrons in energy levels.
Information theory has a quantity that behaves much like entropy in stat mech, but is not actually entropy in stat mech.
BTW: The statement in stat mech would be - Adding energy to a system with negative temperature reduces the number of microstates.
I was under the impression that these are exactly the same, rather than analogous - http://en.wikipedia.org/wiki/Landauer%27s_principle , http://en.wikipedia.org/wiki/Entropy_in_thermodynamics_and_i... and so on (including recent advances).
And when I'm talking about adding a bit of information to the system - that's similar to http://en.wikipedia.org/wiki/Entropy_in_thermodynamics_and_i...
>>> Let's try more specific question. Laundauer's principle requires kT ln 2 of heat for every 1 bit of randomness erased from the system. What about systems with negative T? I can't erase bits?
There is no requirement that information has a physical representation for information-theoretic entropy. Landauer's result assumes that it does have a physical representation, and derives some physical consequences.
But, if I'm not wrong, this requirement could always be satisfied, for any system with two or more microstates.
I'm guessing you've heard of mpeg and h.264 encoding. Which one encodes a movie better? One way of answering this question is to ask: Which codec added less entropy (perhaps for the same compression)?
For that matter: Before Shannon's information entropy, one might wonder if there is a way (another codec) perhaps recovering the information after mpeg coding and decoding. However, now you know that information-entropy can only increase or stay the same, which tells you that subsequent "correction codec" cannot remove entropy introduced by mpeg codec.
Either way, I think we've digressed. I'm actually very happy with yours: "Adding energy to a system with negative temperature reduces the number of microstates.", because this is clear and unambiguous.
I'm saying something slightly different: You can talk about bits in a system without a physical representation; That system can have an information-entropy associated with it. Once you implement a physical system representing those bits, then Landauer's comment applies.
We are not freshman, in natural units (pretty much any system of natural units) Boltzmann's constant is 1. And entropy is measured in bits ('nats', but ln 2 is also equal to 1) ;) . For a system with two microstates entropy would be 1 bit.
+0 K, … , +300 K, … , +∞ K, −∞ K, … , −300 K, … , −0 K."
http://en.wikipedia.org/wiki/Negative_temperature1/T makes more sense
This is one of the 99%
"The Higgs boson is like pearls moving through molasses" or "a celebrity moving through a bar".
"Spacetime is like a big sheet of fabric with a bowling ball on it."
Yeah... no.
"Absolute temperature is usually bound to be positive. Under special conditions, however, negative temperatures—in which high-energy states are more occupied than low-energy states—are also possible..."
Entropy is essentially the (logarithm of) the number of states a system can be in, without changing the macroscopic observables. These states have all the same probability. The second law of thermodynamics is then simply a consequence of the number of allowed transitions of the system. And temperature is the change of the number of states if energy is added to the system. That heat flows from the lower (positive) energy to the higher is then a consequence of calculating the probabilities, as is the observation that heat flows always from a negative to a positive temperature system.
Perhaps a example will make this somewhat clearer: Think of a chain of 20 capacitors, each can be charged or uncharged and I call the 10 left capacitors my left subsystem, and the 10 on the right the right subsystem. Initially there is 1 charged capacitor in the left and 3 in the right. Then the probability that after one charge moves there are two charged capacitors in each subsystem is 9/16 ( since 9 of the uncharged capacitors are on the left). In this case the temperature is positive in both subsystems. (The number of possible configurations of the left 10 capacitors is higher for two charged ones ( 5*4) than for one charged ( 5).
The negative temperature case would in this analogy be, if in one subsystem there are more than 5 charged capacitors. Then there are more charged than uncharged capacitors, the number of allowed states would decrease if I add additional charge. ( I can distribute 9 charges in 10 different ways, but 10 charges just in one way.) But nothing happens about the argument of transition probabilities. If there are 7 charged capacitors on the left and 2 on the right, then after moving a charge the probability that there are 6 and 3 charged ones is 8/11 ( 8 of the 11 uncharged capacitors are on the right).
In the case of the boiling water and the negative (close to zero) system it is the same, it is about counting possible states. And since in one the number of states increases if I add energy ( the temperature is positive) and in the other the number of states increases if I remove energy ( the temperature is negative), both have a preference for transferring energy from the negative energy system to the positive one.
Thank you.
So... overflow? :)
The energy translation used to flip a slight positive temp to a negative temp sounds like a reflection to the negative side of the curve.