Let's say we have removed all elements from the hash. Then all following contains -calls will need to be O(n), if I understood correctly? They need to check every slot in the array to confirm inexistence, rather than just one bucket.
There are cases where contains or get would have to iterate over the whole array, basically when all the previously added elements hash-collide, i.e., are mapped to the same start-index. But every hash-implementation has pathological cases where the access methods get slow -- but if the keys are sufficiently random, you don't expect such cases to occur in practice.