If your motors draw W Watts at peak, and you have N cells at V volts then the peak per-cell current will be (approximately -- there are internal losses) W/(NV) regardless of the geometry of your stacks.
If N is small, your designs may be restricted, but I'll hazard a guess that N will be large for a 30 passenger plane capable of 2 hour flights (e.g. a Tesla model 3 is almost 3000 cells; 31s96p).
The overall point that Im trying to make is that slight battery specific energy density improvements don't matter when compared against the power losses which are proportional to square root of the current.
An airplane under typical operation has a much narrower ranges of power than a Tesla in high power mode. Takeoff power is a low single-digit multiple of cruise power. For my math earlier I used a 3:1 ratio. A Model S Plaid is more like 50:1, or 30:1 for the "regular" Model S.
> The overall point that Im trying to make is that slight battery specific energy density improvements don't matter when compared against the power losses which are proportional to square root of the current.
You've completely missed making that point, since I still haven't seen an argument so far that the current must be very high.