Presumably if you clip against all 6 planes, you get 3+6-2 = 7 triangles in the worst case, which is kind of annoying. However, if you're going to use the AAAB triangle raster method as described in this HN post, then it seems there's no need to clip against left/right/top/bottom planes of the frustum, since it is simpler to just clip the screen-space AABB of the triangle instead. So one just needs to clip against near/far. This is simpler and faster.
I was curious if you had given any thought on that, or if you plan on working on a second book with more details on these nuances.