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Comment by Gualdrapo | Hacker News Reader

> you still have to manually increment the counter in the loop body

It doesn't look like that to me, the ++i thing seems to be just to start printing the array from 1 (I don't know how things are in Python nowadays but I know in Lua arrays start at 1, so there's no need for something like this in there), the value of i is still increasing without telling it explicitly to do so

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Python is 0-indexed. In OP's example, the start parameter makes i start at 1.

Their C++17 example prints starting from 0. Probably a mistake.

If you look at the linked page for C++20[0], other types can be put in the initializer statement, so it's unlikely the loop auto-increments.

[0]: https://www.open-std.org/jtc1/sc22/wg21/docs/papers/2017/p06...

So, it's just a while loop in a for loop's clothing? That's not going to be confusing for people at all...

No, it's a for loop that happens to include an unrelated variable declaration.

Ah, I see. The increment is so they can manually handle the included feature of the other cases, which number of the iteration you're on. Nice that it will automatically loop across a collection, annoying that they couldn't go the whole way and you need to deal with it manually.

No, the increment is necessary to keep the counter going. The choice of pre-increment versus post-increment handles the "start at 1" issue you mentioned, but it isn't auto incrementing.

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