Why would you ever want a == b to not return a bool??
EDIT: Yes, I understand that you can do element-wise equality checks on numpy arrays now
Why would you ever want a == b to not return a bool??
EDIT: Yes, I understand that you can do element-wise equality checks on numpy arrays now
In general, when you get your hands on operator overloading you get a bunch of various quirky applications for each. Some dunder methods have strict runtime-level rules (e.g. __hash__ or __len__), some don't
Expression `select(User).where(User.id == user_id)` does look simpler and cleaner than `select(User).where(eq(User.id, user_id)))`.
Maybe there is an actual eq function of sorts that allows that, and it's not a life-or-death difference here, but as far as convenience goes, it works well. And typecheckers are good enough to be able to let you know what's the return type.
Does a == b true, if all elements are the same? Does it return an array of booleans? It's anyone's guess!
Consider using Shamir secret sharing to share a secret, D, among several people with two people required to recover the secret. D is a positive integer, such as a randomly generated 128 bit AES key you are using to encrypt your launch codes or credit card database.
For anyone not familiar with Shamir secret sharing what you do is pick a prime number, p, that is larger than D and another random positive integer A, that is less than p. Then give each person a pair of numbers, (i, (Ai + D) % p), where each person gets a different i (which should be a positive integer less than p...it is OK to simply use 1, 2, 3, ...). Let's let Di = (Ai + D) % p.
(This is for the case where you want any two people to be able to launch your missiles or decrypt your database. If you wanted 3 required instead of giving out (i, (Ai + D) % p) you would give out (i, (Bi^2 + Ai + D) % p) where B is a randomly chosen positive integer less than p. For 4 required add on a Ci^3 term, and so on).
Given (i, Di) and (j, Dj) and p it is possible to recover A and D.
Here's what that looks like in a language where the big int library uses an accumulator style, i.e., operations are of the form X = X op Y, where the ops are methods on the big int objects. Assume Bi and Bj are big int objects initialized from i and j, and Di and Dj are already big into objects, as is p. This particular example is using Perl. (This is very old code. Since 2002 you can add a "use bigint" pragma to Perl code and then it would look a lot more like the second Python example below).
my $A = $Dj->copy()->bsub($Di); # Dj-Di
$Di->bmul($Bj); # j*Di
$Dj->bmul($Bi); # i*Dj
$Di->bsub($Dj); # j*Di-i*Dj
$Bj->bsub($Bi); # j-i
$Bj->bmodinv($p); # (j-i)'
$Di->bmul($Bj); # (j*Di-i*Dj)*(j-i)'
$Di->bmod($p); # (j*Di-i*Dj)*(j-i)' mod p
$A->bmul($Bj); # (Dj-Di)*(j-i)'
$A->bmod($P); # (Dj-Di)*(j-i)' mod p
At this point, the recovered A is in $A and the recovered D is in $DiHere's what it looks like in a language with the ops as function calls taking the big int objects as arguments. This example is Python without using operator overloading.
import operator as op
def recover(i, j, Di, Dj, p):
j_i_inv = pow(op.sub(j, i), -1, p)
A = op.mod(op.mul(op.sub(Dj, Di), j_i_inv), p)
D = op.mod(op.mul(op.sub(mul(j, Di), op.mul(i, Dj)), j_i_inv), p)
return A, D
Probably more readable than accumulator style. Here it is in Python using its built-in operator overloading for big ints: def recover(i, j, Di, Dj, p):
j_i_inv = pow(j-i, -1, p)
A = ((Dj - Di) * j-i_inv ) % p
D = ((j*Di - i*Dj) * j_i_inv) % p
return A, D
I'd sure rather come across that than either of the earlier examples.OT: this reminds me of something I started to do once but never finished. I was going to write for each language we used at work that had a big int library but that did not support operator overloading a class that implemented a big int RPN calculator. Java, for example. Then recover would look something like this:
calc = new BigRPNCalc();
calc.do(j, i, "-", p, "modinv dup");
calc.do(Dj, Di, "- *", p, "mod swap");
calc.do(j, Di, "*", i, Dj. "* - *", p, "mod");
D = calc.pop();
A = calc.pop();
But I never ended up needing big ints in any of those languages so never really got past some initial design work.Another example might be if you have a domain specific representation of equality (e.g. class Equality)
Could enable a different interface into approximate equality for floating point numbers: Equality.approximate(iota: float) -> bool
```python df.filter( pl.col("foo") == pl.col("bar"), ) ```
Sqlalchemy does something equivalent too, and I'm sure there are many others.
df.filter(pl.col("status") == "active")
In numpy, `x == y` return a boolean vector of the same shape as x and y, comparing them element-wise.In any language, a function called `isEqual` could wipe your hard drive and replace your wallpaper with a photo of a penguin. Therefore, letting programmers pick the names of their functions is bad? No, obviously naming things for least surprise is the programmer's responsibility.
But when it's the symbols `==` instead of an ASCII name, it's a problem in language design?
(FWIW in Javascript, being unable to override == is actually a problem when you want to use objects as Map keys)
I understand why those exist, but they’re pure evil.