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Comment by antonkochubey | Hacker News Reader

if you use \which it'll always be a shell built-in ;) though someone can put a different shell in your .zshrc

  $ which() { echo foo; }
  $ \which
  foo

The backslash only prevents alias expansion.

He meant `command which`

> it'll always be a shell built-in

`command which` wouldn't have been the built-in

`exec /tmp/fake-bash` in bashrc to intercept everything?