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I don't fully get the argument about errors.

in rust say a function returns Result<T, E> so either the we get a result all an error how is that different from (int, err) in go?

do you not still need to handle the error?

in go you just return the error up to whatever the top caller is.

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Go funcs can return both a value and an error, or neither, it's a common gotcha. Having to check the behavior each time is no fun.

Missing error handling is checked at compile-time in Rust (lint-time in Go), and can be enabled for any struct or function (https://doc.rust-lang.org/reference/attributes/diagnostics.h...), not just `Result<T,E>`.

Returning an error to the caller in Rust can be done with a single character.

In Go you can ignore the error value though, and use directly the returned value (`int` in your example). In Rust you cannot do that, you need to unwrap the Result or use the `?`

If the returned value is still valid despite an error, then the function would return (u32, Option<Error>), perfectly valid rust. If the value is meaningless in case of an error then using it is incorrect code; you wouldn't want to do that in either language and rust makes that assumption explicit with unwrap. If you want a default value in case of error just use unwrap_or_default.

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