You can write a C compiler with exactly laid out well-defined semantics. You can't assume those semantics hold for C-the-language, because it doesn't define those semantics. UB is a property of the language, not just of a given compiler. The Rust reference defines the semantics of the safe subset of Rust without any UB, so any compliant Rust compiler won't have UB in that subset. The reference also defines the guarantees which the programmer must uphold within `unsafe` blocks to avoid UB, as long as those are upheld there's no UB at all.