This compiles fine:

    class A {}

    class B1 extends A {}
    class B2 extends A {}

    public class MyClass {
        public static void main(String args[]) {
            A[] array = new B1[1];
            array[0] = new B2();
        }
    }

In TypeScript the following is also valid:

class Something{

    value: Number

class SomethingElse{

    value: Number

    foo: String

    bar: SomeOtherThing[]

function AddSomething(v: Something)

{

    v.value += 1;

var ex = new SomethingElse{

    value: 3,

    foo: “TypeScript is fake types”,

    bar: []

AddSomething(ex);

Why does it work? Because in TypeScript as long as you have a “shape” that fits, it’s the “same type.”

Complete and utter insanity to me, to pretend there’s any real type checking, when types are entirely fake and made up.